Himpunan penyelesaian dari persamaan 2cos3x-akar 3=0,0°<×<120

2 cos3x – √3 = 0, interval 0 < x < 120
2 cos3x = √3
cos3x = (1/2)√3
cos3x = cos30
3x = 30 + 360k
x = 10 + 120k
k = 0 → x = 10°
3x = -30 + 360k
x = -10 + 120k
k = 1 → x = 110°
hp = {10°, 110°}