Himpunan penyelesaian persamaan 2 cos (2x +5/6 pi)=akar 3 lebih besar dari 0,lebih kecil dari pi…

2 cos (2x + 5π/6) = √3

cos (2x + 5π/6) = √3/2

Cos (2x + 5π/6) = cos π/6

2x+5π/6 = π/6 + k.π

2x = -4π/6 + k.π

x = -π/3 + k.π/2

k = 0 –> x = -π/3

k = 1 —> x = π/6

k = 2 —> x = 2π/3

k = 3 —> x = 7π/6

Atau :

2x + 5π/6 = -π/6 + k.π

2x = -π + k.π

x = -π/2 + k.π/2

k = 0 —> x = -π/2

k = 1 —>x = 0

k = 2 —> x = π/2

k = 3 —> x = π

Hp = { π/6, π/2, 2π/3, π}