Hitung lah PH dari larutan Asam sianida /HCN 1 M. ka =6×10^10
Jawaban:
pH = 5-log√6
Penjelasan:
HCN 1 M
Ka =6×10¹⁰
pH = -log[H+]
pH = -log(√Ka × M)
pH = -log(√6×10¹⁰ × 1)
pH = -log(√6×10¹⁰)
pH = -log((√6) × 10⁵)
pH = 5-log√6
Hitung lah PH dari larutan Asam sianida /HCN 1 M. ka =6×10^10
Jawaban:
pH = 5-log√6
Penjelasan:
HCN 1 M
Ka =6×10¹⁰
pH = -log[H+]
pH = -log(√Ka × M)
pH = -log(√6×10¹⁰ × 1)
pH = -log(√6×10¹⁰)
pH = -log((√6) × 10⁵)
pH = 5-log√6