Hitung pH larutan asam bromida (HBr)0,01 M
Jawaban Terkonfirmasi
HBr –> H+ (aq) + Br – (aq)
maka
[H+] = 0,01 M = 10^-2
pH = -log 10^-2 = 2
[H+] = Ma.a krna HBr asam Kuat
[H+] = 0.01.1
[H+] = 1.10^-2
pH = – log [H+]
pH = 2
Hitung pH larutan asam bromida (HBr)0,01 M
HBr –> H+ (aq) + Br – (aq)
maka
[H+] = 0,01 M = 10^-2
pH = -log 10^-2 = 2
[H+] = Ma.a krna HBr asam Kuat
[H+] = 0.01.1
[H+] = 1.10^-2
pH = – log [H+]
pH = 2