Hitunglah 2√3 cos 330° + √3 sin 480° - 1/cosec 60°

Hitunglah 2√3 cos 330° + √3 sin 480° – 1/cosec 60°

= 2 $sqrt{3}$ x 1/2 + $sqrt{3}$ x ( $sqrt{3}$ )/2 – 1/2
= $sqrt{3}$ + 3/2 – 1/2 = $sqrt{3}$ + 1

=(2 akar 3 × 1/2 akar 3) + (akar 3 ×1/2 akar 3) – sin 60°
=(2 × 3 × 1/2) + (3 × 1/2) – 1/2 akar 3
= 3 + 3/2 – 1/2 akar 3
= 6 + 3 – akar 3 / 2
= 9 – akar 3 / 2
= 9/2 – akar 3/2