Hitunglah akar akar persamaan di bawah dengan metode eliminasi,substitusi,geometri

Jawaban:

(1) 2x+3y+4z=6

(2) -3+3y-6z=12

(3) 3x-2y+5z=5

(2) -3+3y-6z=12

3y-6z=15

y=5+2z

(1) 2x+3y+4z=6…(x3)….6x+9y+12z=18

(3) 3x-2y+5z=5…(x2)….6x-4y+10z=10

____________ –

5y+2z= 8

y =(8-2z)/5

y=5+2z=(8-2z)/5

25+10z=8-2z

12z=-17

z=-17/12

y=5+2(-17/12)

y=13/6

2x+3y+4z=6

2x+3(13/6)+4(-17/12)=6

2x+13/2-17/3=6

2x+5/6=6

2x=31/6

x=31/12