Hitunglah integral integral berikut1.∫5 2. (x²+x+1) dx2.∫3 1 4x³ dx​​

Jawab:

Penjelasan dengan langkah-langkah:

integral tertentu

ₐᵇ∫ f(x) dx =  F(x) ]ᵇₐ =  F(b)- F(a)

soal1

₂⁵∫ (x²+ x + 1) dx =

=   [¹/₃ x³ +  ¹/₂ x² + x]⁵₂

=  ¹/₃ (5³-2³) +  ¹/₂ (5²- 2²)  + (5- 2)

= ¹/₃ (125 -8) +  ¹/₂ (25- 4)  + (3)

= ¹¹⁷/₃ +  ²¹/₂+  3

= 52 ¹/₂

soal 2

₁³∫  (4 x³) dx =

=  [ x⁴] ₁³

= (3⁴ – 1⁴)

= 81 – 1

=  80