Hitunglah massa molekul relatif (Mr) senyawa berikut.

A. Na2CO3
→ (2× Ar Na) + (1× Ar C) + (3× Ar O)
→ (2× 23) + (1× 12) + (3×16)
→ 46+12+48
= 106

b. H2SO4
→ (2×Ar H) + (1× Ar S) + (4× Ar O)
→ (2×1)+(1×32)+(4×16)
→ 2+32+64
= 98

c. C6H12O6
→ (6× Ar C) + (12× Ar H) + (6× Ar O)
→ (6×12) + (12×1) + (6×16)
→ 72+11+96
= 179

d. CaCO3
→ (1× Ar Ca) + (1× Ar C) + (3× Ar O)
→ (1×40) + (1×12) + (3×16)
→ 40+12+48
= 100

e. NaCl
→ (1× Ar Na) + (1× Ar Cl)
→ (1×23)+(1×35)
→ 23+35
= 58