1. p = -1, q = 2, dan r = -3
2. p = -2, q = 3, dan r =1
3. p = 1, q = 5, dan r = -2
4. p = 3, q = 2, dan r = -5
Hitunglah nilai p² – 2qr + 3p
A. p² – 2qr + 3p = ( -1 )² – 2 ( 2 x -3 ) + ( 3 x – 1 )
= 1 – ( 2 x -6 ) + ( – 3 )
= 1 – ( -12 ) – 3
= 1 + 12 – 3
= 10
b. p² – 2qr + 3p = ( -2 )² – 2 ( 3 x 1 ) + ( 3 x – 2 )
= 4 – ( 2 x 3 ) + ( – 6 )
= 4 – 6 – 3
= – 5
c. p² – 2qr + 3p = ( 1 )² – 2 ( 5 x -2 ) + ( 3 x 1 )
= 1 – ( 2 x -10 ) + 3
= 1 – ( -20 ) + 3
= 1 + 20 – 3
= 18
d. p² – 2qr + 3p = ( 3 )² – 2 ( 2 x -5 ) + ( 3 x 3 )
= 9 – ( 2 x -10 ) + 9
= 9 – ( -20 ) + 9
= 9 + 20 + 9
= 38
1.) p = -1, q = 2 dan r = -3
p² – 2qr + 3p = (-1)² – 2(2)(-3) + 3(-1)
= 1 + 12 – 3
= 10
2.) p = -2, q = 3 dan r = 1
p² – 2qr + 3p = (-2)² – 2(3)(1) + 3(-2)
= 4 – 6 – 6
= – 8
3.) p = 1, q = 5 dan r = -2
p² – 2qr + 3p = 1² – 2(5)(-2) + 3(1)
= 1 + 20 + 3
= 24
4.) p = 3, q = 2 dan r = – 5
p² – 2qr + 3p = 3² – 2(2)(-5) + 3(3)
= 9 + 20 + 9
= 38
Semoga membantu:)