Hitunglah pembagian bentuk aljabara.42n²÷7n=b.64x⁴÷8x³=c.28a³b÷4a=

By Admin ReiPosted on December 11, 2022

Hitunglah pembagian bentuk aljabara.42n²÷7n=b.64x⁴÷8x³=c.28a³b÷4a=

Jawaban:

$a \ 42 {n}^{2} div 7n = 6n \ 42 div 7 = 6 \ {n}^{2} div n = n \ b \ 64 {x}^{4} div 8 {x}^{3} = 8x \ 64 div 8 = {x}^{4} div {x}^{3} = x \ c \ 28 {a}^{3}b div 4a = 7 {a}^{2} b \ 28 div 4 = 7 \ {a}^{3} div a = {a}^{2}$