Hitunglah pH (a) larutan HCl 1,0×10-3M dan (b) larutan Ba(OH)2 0,020M!​

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Hitunglah pH (a) larutan HCl 1,0×10-3M dan (b) larutan Ba(OH)2 0,020M!​

Rumus :

mmol = V × M

pH = -log [H+]

pH = 14-log [OH-]

[H+] atau [OH-] = a.Ma atau b.Mb

Jawab :

A.

pH = -log [1 × 10-³ M]

= 3-log 1

B.

pH = 14 – (-log [2 . 2 × 10-² M])

= 14 – (-log [4 × 10-² M])

= 10+log 2