Hitunglah pH campuran dari 20ml larutan AgOH 0,3M dengan 40ml larutan HNO3 0,15M (KB = 10^-4)​

Penjelasan:

Rumus :

= (V1 × M1) + (V2 × M2) / V. Total

= (20 mL × 0,3 M) + (40 mL × 0,15 M) / 60 mL

= (6 mmol) + (6 mmol) / 60 mL

= (12 mmol) / 60 mmol

= 0,2 mmol

pOH = -Log (√ Kb × Mb )

pOH = -Log (√ 10^-4 × [2 × 10^-1 M] )

pOH = -Log (√ 2 × 10^-5 )

pOH = -Log ( 1 × 10^-4 )

pOH = 14 – ( 4 -Log 1 )

pOH = 14 – ( 4 )

pOH = 10