Ini gimana ya caranya?

³log a – 2(³log b) ≤ 1
³log (a/b²) ≤ 1
a/b² ≤ 3

³log b – 2(³log a) = -2
³log (b/a²) = -2
b/a² = 1/9
b = 1
a² = 9
a = 3

jadi a x b = 3 x 1 = 3
B