Integral (18x^2)/√(2x^3+8) dx

Integral (18x^2)/√(2x^3+8) dx=
Misal:
# U = 2x³ + 8
Du = 6x² dx
# kalikan 3 pd ke-2 ruas
~ 3 du = 18x² dx
Int (18x^2)/√(2x^3+8) dx
= int 3/√u du
= int 3 × U^-½ du
= 3/½ U^½ + c
= 6×U^½ + c
= 6√U + c
= 6√(2x³ + 8) + c