Integral 2x+1 / √x^2+x-4 dx

Integral 2x+1 / √x^2+x-4 dx

Jawaban Terkonfirmasi

$displaystyle text{misal:}\x^2+x-4=u\2x+1,dx=du\\intfrac{2x+1}{sqrt{x^2+x-4}},dx=intfrac{du}{sqrt{u}}\intfrac{2x+1}{sqrt{x^2+x-4}},dx=int u^{-frac12},du\intfrac{2x+1}{sqrt{x^2+x-4}},dx=2u^{frac12}+C\boxed{boxed{intfrac{2x+1}{sqrt{x^2+x-4}},dx=2sqrt{x^2+x-4}+C}}$