Integral batas atas p batas bawah 0 ( 4x + 5 ) dx = -3 tentukan nilai p

By Admin ReiPosted on October 29, 2022

Integral batas atas p batas bawah 0 ( 4x + 5 ) dx = -3
tentukan nilai p

Jawaban Terkonfirmasi

$$begin{align} displaystyleintop_0^pleft(4x+5right) dx&=-3\[8pt] left[2x^2+5xright]_0^p&=-3\[8pt] left(2p^2+5pright)-left(2(0)^2+5(0)right)&=-3\[8pt] 2p^2+5p&=-3\[8pt] 2p^2+5p+3&=0\[8pt] (2p+3)(p+1)&=0 end{align}$
$boxed{p=-dfrac32}$ atau $boxed{p=-1}$

Gambar Jawaban