Integral , cari nilai p jika *(1-x)dx=0.P>​

Jawab:

#dirumahsajalah

p..o ∫ x ( x – 1) dx = 0

p..o ∫ (x² – x ) dx = 0

= [ 1/ 3 x³ – 1/2 x²] p…o= 0

1/3 p³ – 1/2 p² = 0

1/2 p ² ( 2/3 p – 1 ) =0

p= 0 atau 2/3 p = 1 –> p = 3/2

p > 0 maka p = 3/2