Integral ln(1-x)dx , tolong yang bisa bantu

Jawab

u = 1- x
u' = -  dx

∫ ln ( 1- x)  dx
=  – ∫  ln (u) du
= – { u ln u – u )
= – u ln u + u
= -(1-x) ln (1- x) + (1- x)
= – ln (1-x) + x ln (1-x) + (1 – x) + c