Integral sin (2x-3) dx..??

u = 2x – 3
du = 2 dx
( 1 / 2 ) du = dx

( 1 / 2 ) * int [ sin u du ]
= ( 1 / 2 ) * ( – cos u ) + C
= ( – 1 / 2 ) cos u + C
= ( – 1 / 2 ) cos ( 2x – 3 ) + C