Integral (x√x+√x)dx

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Integral (x√x+√x)dx

Integral (x√x+√x)dx
= integral (x.x^1/2 + x^1/2)dx
= integral (x^3/2 + x^1/2)dx
= 1 per 3/2+1 x^3/2+1 + 1 per 1/2+1 x^1/2+1 + C
= 1 per 5/2 x^5/2 + 1 per 3/2 x^3/2 + C
= 2/5 x^5/2 + 2/3 x^3/2 + C
= 2/5 x²√x + 2/3 x√x + C