Integral x+1 dibagi 9x²+18x+10 dx =

Integral x+1 dibagi 9x²+18x+10 dx =

SOAL:

∫ (x+1)/(9x²+18x+10) dx

JAWAB:

gunakan integral substitusi

∫

$frac{x + 1}{9 {x}^{2} + 18x + 10 } frac{d( 9{x}^{2} + 18x + 10) }{18x + 18} =$

∫

$frac{(x + 1)}{(9 {x}^{2} + 18x + 10) } frac{d(9 {x}^{2} + 18x + 10) }{18(x + 1)} =$

adalah:

$frac{1}{18} ln |9 {x}^{2} + 18x + 10 | + c$