Invers fungsi fx=2x+1/x-3, x≠3

F(x) = (2x + 1) / (x – 3)
Jika f(x) = (ax + b) / (cx + d)
f^(-1)(x) = ( -dx + b) / (cx – a)
a = 2 , b = 1 , c = 1 , d = -3
Maka f^(-1)(x)
= (3x + 1) / (x – 2)

F(x)=y

2x+1/x-3=y
xy-3y=2x+1
xy-3y-1=2x
xy-2x=1+3y
x=1+3y/(y-2)

sehingga inversnya
3x+1/x-2

sekian. terima kasih.

jangan tertatih, tetap berlatih.