Jari jari suatu kerucut 8cm garis pelukisnya 17 cm berapa cm³ volume kerucut tersebutt​

Jawaban:

~Bangun ruang

t^2 = s^2 – r^2

= 17^2 – 8^2

= 289 – 64

= 225

= √225

= 15 cm

V = 1/3 × π × r × r × t

= 1/3 × 3,14 × 8 × 8 × 15

= 1/3 × 3.014,4

= 3.014,4/3

= 1.004,8 cm^3

Tinggi Kerucut

T² = S² – R²

= 17² – 8²

= 289 – 64

= √225

= 15 Cm

Volume Kerucut

= ⅓πr²t

= ⅓ × 3,14 × 8² × 15

= 1 × 3,14 × 64 × 5

= 3,14 × 320

= 1.004,8 Cm³.

~Opung~