Jawablah bentuk aljabar dibawah! (2х-3) (4x²+6x+9)=​

Jawaban:

= (2x – 3)(4x² + 6x + 9)

= 2x (4x² + 6x + 9) – 3(4x² + 6x + 9)

= 8x³ + 12x² + 18x – 12x² – 18x – 27

= 8x³ + 12x² – 12x² + 18x – 18x – 27

= 8x³ – 27