Jenis akar akar persamaan kuadrat dari 2x²-4x+1=0​

Jawaban:

x1 = 1/2 × (2 + √2)

x2 = 1/2 × (2 – √2)

Penjelasan dengan langkah-langkah:

x1,2 = [-(-4) ± √((-4)² – 4(2)(1))] : 2(2)

= [4 ± √(16 – 8)] : 4

= [4 ± √8] : 4

= [4 ± 2√2] : 4

= [2 (2 ± √2)] : 4

x1 = 1/2 × (2 + √2)

x2 = 1/2 × (2 – √2)