Jika a dan b adalah akar2 persamaan kuadrat 3×2-4x+5=0,maka 1/a+1/b=

3x² – 4x + 5 = 0

α + β = -b/a = -(-4)/3 = 4/3

α x β = c/a = 5/3

.
1/α + 1/β

= β/αβ + α/αβ

= (β + α)/(αβ)

= (α + β)/(αβ)

= (4/3)/(5/3)

= 4/5