Jika a=2 b=-3 c=4 hitunglah nilai dari a.-3(a+b+c) b.ab+ac-bc c.5b+(a+c) d.5ab+5bc)​

a.=-3(a+b+c)

=-3 × (2+(-3)+4)

=-3 × 3

=(-9)

b.=ab + ac – bc

=(2×(-3)) + ( 2 × 4 ) – (-3×4)

= -6 + 8 – (-12)

= 2-(-12)

= 2 + 12

= 14

c.=5b + ( a+c)

= 5 ×(-3) + (2+4)

= -15 + 6

= -9

d.=(5ab + 5bc)

= [( 5 × 2 × (-3) + (5 × 2 × 4)]

= [(-30) + (40)]

= 10