Jika bangunan ABCD dan AEFG sebangun luas bangunan AABCD adalah

Jawaban:

CD/FG = BC/EF

CD/ 6 = 15/10

CD = 6 x 15 : 10

CD = 9 cm

AG =√10²-6²=√100-36=√64= 8 cm

AD/AG = BC/EF

8+DG/8 = 15/10

10(8+DG) = 8 x 15

80 + 10 DG = 120

10 DG = 120 -80

10DG = 40

DG = 40 :10 = 4cm

AD = AG+DG = 8+4 = 12cm

AB/AE = BC/EF

12+BE/12 = 15/10

10(12+BE) = 12 x15

120 + 10 BE = 180

10 BE = 180 – 120

10 BE = 60

BE = 60: 10 = 6cm

AB = AE+BE =12+6 = 18 cm

Luas ABCD=1/2 (AB+CD) AD

= 1/2 ( 18 +9) 12

= 162 cm² A

maaf kalo salah