jika di ketahui persamaan kuadrat ax^2 + bx – 2 =0 yang mempunyai akar akar 1/5 &1/2 tentukan nilai a dan b

X1 * x2 = c/a
(1/5)(1/2) = -2/a
1/10 = -2/a

a = -2(10)
a = -20

x1 + x2 = -b/a
1/5 + 1/2 = -b/-20
2/10 + 5/10 = b/20
7/10 = b/20
14/20 = b/20

b = 14

jadi, a = -20 dan b = 14