Jika diketahui f(x) = x – 3 dan g(x) = x² + 2x, maka nilai (g ₀ f) (x) adalah?

gof(x) = g { f(x) }

=  g ( x – 3 )

=  ( x  - 3 )²   + 2 (x – 3)

=  x² – 6x + 9 + 2x – 6

=  x² – 4x  + 3

Gof(x) = g(f(x))
= (x – 3)^2 + 2(x – 3)
= x^2 – 6x + 9 + 2x – 6
= x^2 – 4x + 3