Jika diketahui log 2 = a dan log 3 = b maka log 120 adalah?

Log 120
= log (2^3.3.5)
= log 2^3 + log 3 + log 5
= 3.log 2 + log 3 + log (10/2)
= 3a + b + log 10 – log 2
= 3a + b + 1 – a
= 2a + b + 1

Log 120
= log (2 x 2 x 3 x 10)
= log 2 + log 2 + log 3 + log 10
= a + a + b + 1
= 2a + b + 1