Jika f adalah fungsi linear, f(10) = 2.021 , dan f(x+3)+19=f(x), tentukan nilai f(131).​

Materi : Fungsi dan Relasi

f(10) = 2.021

_________/

f(10) = f(10+3) + 19

2.021 = f(13) + 19

f(13) = 2.002

______________/

10a + b = 2.021

13a + b = 2.002

____________- Eliminasi ( b )

10a – 13a = 2.021 – 2.002

– 3a = 19

a = 19/-3

[ a = -6⅓ ]

()()()()()()()()()

b = 2.021 – 10a

b = 2.021 – 10( – 19/3 )

b = 2.021 + 190/3

b = 2.021 + 63⅓

[ b = 2.084⅓ ]

Hasil / Result :

( a = – 19/3 dan b = 2.084⅓ )

Fungsinya : f(x) = – ( 19/3 )x + 2.084⅓ )

Nilai f(131) = – 829⅔ + 2.084⅓ = 1.254⅔

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