Jika (f•g) (x) =x²-x+1 dan g(x) =x-1 maka nilai dari f(-2)=​

Misal
g(x) = m

m = x – 1
x = m + 1

f o g(x) = x² – x + 1
f(g(x)) = x² – x + 1
f(m) = (m + 1)² – (m + 1) + 1
f(m) = m² + 2m + 1 – m – 1 + 1
f(m) = m² + m + 1

f(-2) = (-2)² + (-2) + 1
f(-2) = 4 – 2 + 1
f(-2) = 3

Misal : x – 1 = x
fog(x) = x² – x + 1
(x-1)² + ax + n = x² – x + 1
x² – 2x + 1 + (1) (x-1) + n = x² – x + 1
0 + n = 1
n = 1
n = 1
maka f(x) = x² + x + 1
f(-2) = 4 – 2 + 1 = 3