Jika f(x) = 〖2x〗^2- 4x – 5 nilai dari f(2) + f(1) adalah​

Jawaban:

f ( 2 )

= 2x^2 + 4x + 5

= 2 ( 2 ) ^2 + 4 ( 2 ) + 5

= 8 + 8 + 5

= 21

f ( 1 )

= 2x^2 + 4x + 5

= 2 ( 1 ) ^2 + 4 ( 1 ) + 5

= 2 + 4 + 5

= 11

f ( 2 ) – f ( 1 ) = 21 – 11 = 10

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