Jika f(x) = 2/3x -6 dan g(x) = 2x+1/2, maka (g o f) (x) =
(gof)(x) = g(f(x))
= g(2x – 1)
= (2x – 1) – 2 / 3(2x – 1)
= 2x – 3 / 6x – 3
Jika f(x) = 2/3x -6 dan g(x) = 2x+1/2, maka (g o f) (x) =
(gof)(x) = g(f(x))
= g(2x – 1)
= (2x – 1) – 2 / 3(2x – 1)
= 2x – 3 / 6x – 3