Jika f(x) = S(⅓x²– 2x+5) dxdan f(0) = 5, maka f(x) = …
Penyelesaian:
∫ (1/3 x^2 – 2x + 5) dx
= (1/3 . 1/3) x^3 – (2/2) x^2 + 5x + C
= 1/9 x^3 – x^2 + 5x + C
f (0) = 5
1/9 x^3 – x^2 + 5x + C = 5
0 – 0 + 0 + C = 5
C = 5
maka f (x) = 1/9 x^3 – x^2 + 5x + 5
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Detil Jawaban
Kelas: 11
Mapel: Matematika
Bab: Integral Tak Tentu
Kode: 11.2.10
Kata Kunci: integral, rumus f (x)