Jika f(x) = x²-3x+2 dan g(x) = x+1 maka ( f o g ) ( x ) adalah​

fungsi komposisi

(fog)(x)

= f(g(x))

= f(x + 1)

= (x + 1)² – 3(x + 1) + 2

= x² + 2x + 1 – 3x – 3 + 2

= x² – x

f(x) = x² – 3x + 2

g(x) = x + 1

(f o g)(x) = … ?

→ (f o g)(x) = f(g(x))

f(g(x)) = f(x + 1)

= (x+1)² – 3(x + 1) + 2

= x² + 2x + 1 – 3x – 3 + 2

= x² – x