Jika f(x)=0,2(1/5)^x,tentukan nilai f(-3)

F(x)=0,2(1/5)^x
f(x) = 2/10 (1/5)^x
f(-3) = 2/10 ( 1/5)-³
f(-3) = 2/10 (1-³/5-³)
f(-3) = 2/10 (5³/1³)
f(-3) = 1/5 (125)
f(-3) = 25