Jika f(x)=2x-3 dan g(×)=x pangkat 2 maka f(4)-g(2) adalah
F(4)= 2(4)-3 = 8-3=5
g(2) =2²=4
jadi f(4)-g(2)= 5-4=1
F(x) = 2x – 3
f(4) = 2(4) – 3 = 8 – 3 = 5
g(x) = x²
g(2) = 2² = 4
Jadi, f(4) – g(2) = 5 – 4 = 1
Jika f(x)=2x-3 dan g(×)=x pangkat 2 maka f(4)-g(2) adalah
F(4)= 2(4)-3 = 8-3=5
g(2) =2²=4
jadi f(4)-g(2)= 5-4=1
F(x) = 2x – 3
f(4) = 2(4) – 3 = 8 – 3 = 5
g(x) = x²
g(2) = 2² = 4
Jadi, f(4) – g(2) = 5 – 4 = 1