Jika f'(x)3x²+4x dan f(2)=3,maka f(x)=…..

f'(x) = 3x² + 4x

f(x)

= ∫ 3x² + 4x dx

= x³ + 2x² + C

f(2) = 3

2³ + 2(2) + C = 3

8 + 4 + C = 3

12 + C = 3

C = 3 – 12

C = -9

f(x) = x³ + 2x² – 9