Jika f(x)=x-2, g(x)=x2+2x-3, dan (fohog)=x2+6. maka h(5) adalah

Fungsi komposisi

f(x)= x – 2
g(x) = x² + 2x – 3
(fohog)(x) = x² +6
.
f { h(x²+2x-3)} = x²+ 6
h(x²+2x-3) -2 = x² + 6
h(x²+2x-3) = x² + 8
.
h(5)= …
x²+2x -3  = 5
x² +2x – 8 = 0
(x +4)(x-2) = 0
x= -4  atau x = 2
.
x= -4 –> h(5)= (-4)² +8 = 24
x =2 –> h(5)= (2)² + 8 = 12