Jika garis y + x= a menyinggung parabolay=-1/3x²+x+2 maka nilai ay=-1/3x²+x+2

Jawab:

x+y= a

y = a-x

y= -⅓ x² + x + 2

a+x = -⅓x² + x + 2

⅓x² – x – x + a-2 =0

⅓x² – 2x + a-2 = 0

a= ⅓ b= -2 c= a-2

D=0

b² – 4ac = 0

(-2)² – 4(⅓)(a-2) = 0

4 – 4/3 (a-2) =0

4 – 4/3a + 8/3 = 0

12 – 4a + 8 = 0

-4a = -20

a = 5

Semoga membantu 😉