Jika g(x) = 1/x + x^3 – √2x, maka dg(x)/dx = . . . .

-1/x² + 3x² – 1/√2x

Pembahasan

g (x) = a . xⁿ

dg(x)/dx = n . axⁿ⁻¹

g (x) = 1/x + x³ – √2x

g (x) = x⁻¹ + x³ – √2x

dg(x)/dx = -x⁻¹⁻¹ + 3x³⁻¹ – 1/√2x

dg(x)/dx = -x⁻² + 3x² – 1/√2x

dg(x)/dx = -1/x² + 3x² – 1/√2x

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Detil Jawaban

Kelas: 11

Mapel: Matematika

Bab: Turunan Fungsi Aljabar

Kode: 11.2.9

Kata Kunci: turunan pertama