Jika g(x) = x + 3 dan (fog)(x) = x² 4, maka persamaan dari f(x-2)

komposisi fungsi

koreksi soal

(fog)(x) = x² – 4

g(x) = x + 3

(fog)(x) = x² – 4

f(x + 3) = x² – 4

f(x + 3 – 5) = (x – 5)² – 4

f(x – 2) = x² – 10x + 25 – 4

f(x – 2) = x² – 10x + 21