Jika harga ta ch3cooh=10pangkat -5 tentukan ph lanjutan ch3cook 0,01m

PH = 1/2 (14 + pKa + log[G])
pH = 1/2 (14 + (-log10^-5) + log10^-2)
pH = 1/2 (14 + 5 – 2)
pH = 1/2 (17)
pH = 8,5