Jika Ka CH3COOH 1,8 x 10^-5, pH larutan CH3COOH 0,02 M adalah..
[H+]=√Ka.M =√ 1,8 x 10^-5 x 0,02 =√36 x 10^-8=6x 10^-4
pH=-log[H+]=4-log 6
Jika Ka CH3COOH 1,8 x 10^-5, pH larutan CH3COOH 0,02 M adalah..
[H+]=√Ka.M =√ 1,8 x 10^-5 x 0,02 =√36 x 10^-8=6x 10^-4
pH=-log[H+]=4-log 6