Jika keliling EFGH 40 cm,panjang sisi EF dan FG berturut-turut adalah…dan sisi EF(x+2) dan FG(x).

K = 2 (ef+fg)
40 = 2 (x+2+x)
40 = 2 (2x+2)
40 = 4x + 4
10 = x + 1
x = 10 – 1 = 9

*ef = (x+2) = (9+2) = 11cm
*fg = x = 9cm

done(: