Jika masa KOH(Mr=56)adalah 14 gr dilarutkan dalam 310gr air, berapa kemolalan larutan itu

Jawaban:

Mol = 14 / 56 = 0,25 mol

M ( molal) = 0,25/310 = 0,0008 = 8 x 10^-4 M

M = n/v

n = massa/mr
n = 14/56
n = 0,25

M = n/v
= 0,25/310
= 0,0008
= 8 x 10*-4