Jika sin b cos (theta - a) = sin a cos (b - theta) maka sin (a-b) =...

Jika sin b cos (theta – a) = sin a cos (b – theta) maka sin (a-b) =…

Jawaban Terkonfirmasi

Dengan demikian:

$$begin{align}sin bcos(theta-a)&=sin acos(b-theta) \ sin b(costhetacos a+sinthetasin a)&=sin a(cos bcostheta+sin bsintheta) \ cos asin bcostheta+sin asin bsintheta&=sin acos bcostheta+sin asin bsintheta \ cos asin bcos theta&=sin acos bcostheta \ sin acos bcostheta-cos asin bcos theta&=0 \ sin acos b-cos asin b&=0 \ sin(a-b)&=0 end{align}$