Jika X1 dan X2 merupakan penyelesaian dari 2x^ +3x+5=0. maka nilai x1 dan x2 adalah

2x^2 + 3x + 5 =O
(2x + 1)(x + 2) =0
lalu didalam kurung tsb di ambil satu"
2x+ 1 = 0
2x = -1
x = – 1/2 utk x 1

x+2 =0
x = -2 utk x 2
smg membantu

2x^2 + 3x + 5 = 0
 x1 + x2 = -b /a = -3/2 
x1 x2 = c/a = 5/2
x1 = 5/2 x2

sub. x1 = 5/2 x2
x1 + x2 = – 3/2
5/2 x2 + x2 = -3/2
7/2 x2 = -3/2 
x2 = -6/ 14 = -3/7 

sub. x2 = -3/7
x1 = 5/2 (-3/7)
x1 = -15/14

jadi, x1 = -15/14 ,  x2 = -3/7